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 Posted: Wed Jul 05, 2006 3:04 pm
Invictus_88 Um, ah..
..thing is, we're looking for two representatives. Then you look for two in the Schwartz set and stop there.
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Posted: Wed Jul 05, 2006 3:15 pm
Angra-Mainyu Invictus_88 Um, ah..
..thing is, we're looking for two representatives. Then you look for two in the Schwartz set and stop there.
Also, any ideas as regards that UNG graphic?
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Posted: Wed Jul 05, 2006 3:53 pm
Here's my first contribution. It's a work in progress. 
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Posted: Thu Jul 06, 2006 2:48 am
Lord Jagged Here's my first contribution. It's a work in progress.
Not bad but we really don't want to look too much like the UN!
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Posted: Thu Jul 06, 2006 6:54 pm
Angra-Mainyu The Schwartz set approach is the more intutitive way of finding the winner using the Schulze method. The path approach is the more formal math way of thinking. All you do is find the person people prefer. If there is no one candiate who is preferred on average to all the rest, then you find the candidate who suffered the greatest defeat and eliminate them. Say we have four candiates: A, B, C, and D, and the preference [a preference is expressed if they are ranked higher by the voter] is as follows: A > B : 55/45 A > C : 60/40 B > C : 51/49 B > D : 60/40 C > D : 70/30 D > A : 51/49 A beats B and C; loses to D B beats C and D; loses to A C beats D; loses to A and B D beats A; loses to B and C The Schwartz set is defined as the collection of candidates who are unbeaten by anyone outside the set and there are no subsets that also fufill the propety. In this case it is {A, B, C, D} and we have no winner; so we have to get rid of someone. D suffered the greatest loss [70/30 to C] so they are ejected. Now, ignoring all results with D: A > B : 55/45 A > C : 60/40 B > C : 51/49 A beats B and C; no losses B beats C; loses to A C loses to A and B We can now safely exclude C from the Schwartz set because it loses to everyone, making our first attempt at forming the set {A, B}. But, if you look at {A, B}, then B also losses to everyone in {A, B} so we can form the subset {A}. This is the Schwartz set. A is the winner.
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Posted: Fri Jul 07, 2006 11:59 am
Well, if our resident physicist is able to sort it out then I'll happily do what I can to help.
Have we any consensus on the logo?
If so, can you drop a comment on the main thread?
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Posted: Fri Jul 07, 2006 2:17 pm
Invictus_88 Well, if our resident physicist is able to sort it out then I'll happily do what I can to help.
Have we any consensus on the logo?
If so, can you drop a comment on the main thread? What about us who don't have a clue?
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Posted: Sat Jul 08, 2006 8:31 am
Mr. Bono Vox Invictus_88 Well, if our resident physicist is able to sort it out then I'll happily do what I can to help.
Have we any consensus on the logo?
If so, can you drop a comment on the main thread? What about us who don't have a clue?
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Posted: Mon Jul 10, 2006 8:16 pm
Invictus_88 Mr. Bono Vox Invictus_88 Well, if our resident physicist is able to sort it out then I'll happily do what I can to help.
Have we any consensus on the logo?
If so, can you drop a comment on the main thread? What about us who don't have a clue? Yes but I want to be able to figure the vote out as well.
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Posted: Fri Jul 14, 2006 1:41 pm
Invictus_88 Um, ah..
..thing is, we're looking for two representatives. You can get two representatives from the Schwartz. At least it looks possible, I'm not sure what method you'd use though, looks like theres 2 ways. They might get the same though question B seems to be second both ways. A > C gives the next biggest loss, ignoring the one that D lost in. Which means B is the only one left (Might work better with more letters). And A and B were left after Quote: We can now safely exclude C from the Schwartz set because it loses to everyone, making our first attempt at forming the set {A, B}. Oh, I prefer the Schwartz thing because I think I can understand it, more than the other one anyway. And you need to know matrixs and you need thought them.
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Shadow of an Illusion Crew
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Posted: Sun Jul 16, 2006 8:13 am
Well, we'll do that then. Iguana'll have to organise the poll though because I'm not sure how to orchestrate it.
Canada has already chosen their representatives, or from another angle, so far only one country has finished selecting their representatives.
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Posted: Sun Jul 16, 2006 3:19 pm
Invictus_88
Well, we'll do that then. Iguana'll have to organise the poll though because I'm not sure how to orchestrate it.
Canada has already chosen their representatives, or from another angle, so far only one country has finished selecting their representatives.
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Posted: Tue Jul 18, 2006 11:42 am
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Posted: Tue Jul 18, 2006 1:14 pm
Invictus_88 http://i64.photobucket.com/albums/h195/1492AD/guildlogo.jpg Have we any preferences?I don't really like the ones that have a plain world. The ones on the right. And ung makes me think of cavemen.
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Shadow of an Illusion Crew
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Posted: Tue Jul 18, 2006 1:23 pm
I prefer Jagged's logo.
I don't get the voting. Why can't we just have a straight vote and whichever two have the most votes wins?
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Reply
